Question 981052
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Z\ =\ \frac{134\ -\ 100}{15}\ \approx\ 2.267]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ P(Z\,>\,2.267)\ =\ 1\ -\ P(Z\,<\,2.267)]


You can look this up in a table or use *[tex \Large1 - NORM.S.DIST(34/15,TRUE)] in Excel


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \