Question 980984
{{{p=I*(1.03)^t}}}
p, population
I, starting population
t, time in years


When t for double p?

{{{1*1.03^t=2}}}
{{{log(10,1.03^t)=log(10,2)}}}
{{{t*log(10,1.03)=log(10,2)}}}
{{{highlight(t=log(10,2)/log(10,1.03))}}}


{{{23&1/2*years}}}