Question 980982
...Meaning that what values would make {{{x^2-6x=0}}}.


Requirement to find, {{{x(x-6)<>0}}}
{{{x<>0}}}  and {{{x<>6}}}.


{{{f(g(x))=1/(x^2-6x)}}} will be undefined if the denominator were 0; meaning if the variable x were 0 or 6.