Question 980893
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x=one number; y=other number
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{{{x=2y-1}}}
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{{{x^2-y^2=16}}}
{{{(2y-1)^2-y^2=16}}}
{{{4y^2-4y+1-y^2=16}}}
{{{3y^2-4y-15=0}}}*[invoke quadratic "y", 3, -4, -15 ]
y=3 or y=-1.67
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For y=3:
x=2y-1=2(3)-1=6-1=5
ANSWER 1: The numbers are 5 and 3 
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For y=-1.67:
x=2y-1=2(-1.67)-1=-4.34
ANSWER 2: The numbers are -1.67 and -4.34