Question 980843
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Let *[tex \Large x] represent the first number.  Then the second number must be *[tex \Large 4x\ + 8].  The product of these two numbers is *[tex \Large x(4x\ +\ 8)] and is equal to 192, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x^2\ +\ 8x\ -\ 192\ =\ 0]


Solve the factorable quadratic and discard the negative root.  Then calculate *[tex \Large 4x\ +\ 8]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \