Question 83699
The given expression is:  


{{{x^3 = 2x^2 + 8x}}}


This cna be written as:   



{{{x^3 - 2x^2 - 8x = 0 }}} 



Here, we observe that "x" can be taken as the common factor. So, we will take out "x" as the factor;


{{{x(x^2 - 2x - 8) = 0 }}} 



==> x = 0 or {{{(x^2 - 2x - 8) = 0 }}} 


==> x = 0  or {{{x^2 - 4x + 2x - 8 = 0 }}} 


==> {{{x(x - 4) + 2(x - 4)= 0 }}} 


==> x = 0 or x = 4 or x = -2 


hence, the solution.