Question 980702
<pre>
 5,8,11,14,17

Start with 5
Add 3 1 time to 5 to get the 2nd term, 5+3*1 = 5+3 = 8
Add 3 2 times to 5 to get the 3rd term, 5+3*2 = 5+6 = 11
Add 3 3 times to 5 to get the 4th term, 5+3*3 = 5+9 = 14
Add 3 4 times to 5 to get the 5th term, 5+3*4 = 5+12 = 17
...
... so,
Add 3 99 times to 5 to get the 100th term, 5+3*99 = 5+297 = 300

Or use formula which is the same idea:

{{{a[n]=a[1]+(n-1)*d}}}

n=100, a<sub>1</sub>=5, d=3

{{{a[100]=5+(100-1)*3}}}

{{{a[100]=5+(99)*3}}}

{{{a[100]=5+297}}}

{{{a[100]=300}}}

Edwin</pre>