Question 980491
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ S\ =\ \frac{rL\ -\ a}{r\ -\ 1}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ S(r\ -\ 1)\ =\ rL\ -\ a]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Sr\ -\ S\ =\ rL\ -\ a]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Sr\ -\ rL\ =\ S\ -\ a]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r(S\ -\ L)\ =\ S\ -\ a]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r\ =\ \frac{S\ -\ a}{S\ -\ L}]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \