Question 980560
Solver the given trig equation exactly on 0<=theta<2pi

question is: 2cos(theta/2)= -sqrt2

So far I divided the 2 on the left and the right side of the equation leaving me with, Cos(theta/2)= -sqrt2/2
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Use the double angle formula:
cos(2t) = 2cos^2(t) - 1
= 2*(1/2) - 1
cos(theta) = 0
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theta = pi/2, 3pi/2