Question 980516
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A=area; L=length; {{{W[1]}}}=original width; W[2])))=new width
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{{{A=LW[1]}}}
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Length increase by 6%, same area.
{{{A=(1.06L)(W[2])}}} Substitute for A.
{{{LW[1]=(1.06L)(W[2])}}} Divide each side by L.
{{{W[1]=1.06W[2]}}} Divide each side by 1.06.
{{{W[1]/1.06=W[2]}}} Convert 1/1.06 to decimal.
{{{0.9434W[1]=W[2]}}}
The new width to keep the same area is 94.34% of the original,
for a decrease of 5.66%.