Question 980463
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This is a L'Hôpital indeterminate form *[tex \Large \ \ \lim_{x\right\infty}\,\frac{f(x)}{g(x)}\,=\,\frac{\infty}{\infty}]


So evaluate


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \lim_{x\right\infty}\,\frac{f'(x)}{g'(x)}\ =\ \frac{8x}{-2x}\ =\ -4]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \