Question 980428
P, and Q, and the center, are collinear.  You can find the slope of this line, and then calculate the negative reciprocal of this slope.


If point C is the center of this circle, m is slope of the two points CQ, then you want  to know {{{-1/m}}} for the perpendicular line you want to find.


Use the point-slope form of linear equation and form the equation accordingly, and then transform into whatever form you want.  Here, you already know as given the desired line must go through center  (-4,-2):
{{{y-(-2)=(-1/m)(x-(-4))}}}
... Do what you need.