Question 980394
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If you have two or more ordered pairs where the abscissas are equal but the ordinates are different, then the relation is NOT a function.  Otherwise it is a function.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \