Question 980388

let's number be {{{x}}}
when {{{40}}}% or {{{40/100}}} of a number is added to {{{42}}} the result is the number itself, then the number is

{{{(40/100)x+42=x}}}.....solve for {{{x}}}

{{{42=x-(40/100)x}}}

{{{42=(100/100)x-(40/100)x}}}

{{{42=(60/100)x}}}

{{{42/(60/100)=x}}}

{{{(42*100)/60=x}}}

{{{4200/60=x}}}

{{{420/6=x}}}

{{{70=x}}}

so, the number is {{{70}}}


check:

if the number is {{{70}}}, than {{{(4cross(0)/1cross(0)cross(0))7cross(0)=4*7=28}}}

if {{{28}}} added to {{{42}}} we have {{{28+42=70}}} which is a number itself