Question 980377
The probabilities have to add to 1
If one is 0.06, the other has to be (1-0.06)=0.94

10C3=
10!/7!3!
10*9*8*7!/7!*3*2*1

The 7! cancel
10*9*8/3*2*1
720/6=120
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Three are 421 outcomes
A=39/421 =0.0926
C=258/421=0.6128
D=124/421=0.2945
That adds up to 0.9999.
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632/(632+352)
632/984
0.6423