Question 980243
{{{y = 3*sin(2pi*x)}}} is in the form {{{y = A*sin(B*x)}}} where |A| is the amplitude and {{{2pi/B}}} is the period.


A = 3 ----> |A| = |3| = 3 is the amplitude


{{{B = 2pi}}}, so {{{2pi/B = (2pi)/(2pi) = 1}}} is the period


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Amplitude = <font color="red">3</font>


Period = <font color="red">1</font>