Question 980221
“An object is thrown directly upward from a starting height of 25 ft and a starting velocity of 85 ft per second. The following function describes the height of the object with respect to the time, t.”

h(t) = -16t2 + 85t + 25

How long does it take before the object reaches the ground? Round you answer to 

the nearest hundredths place.

The answer is 5.59.
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Use ^ (Shift 6) for exponents.

h(t) = -16t^2 + 85t + 25
It hits the ground when h(t) = 0
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h(t) = -16t^2 + 85t + 25 = 0
Solve for t
*[invoke solve_quadratic_equation -16,85,25]
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t = ~ 5.59 seconds
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Ignore the negative solution.