Question 980208
Hi there,
y = 3x^3 - 6x^2 - 9 
dy/dx = 9x^2 - 12x
dy/dx = 0
9x^2 - 12x = 0
3x(3x - 4) = 0
3x = 0 
x = 0
Substituting x = 0
into f(x)
3x^3 - 6x^2 - 9
3(0)^3 - 6(0)^2 - 9
= -9
Turning point (0, -9)
.......
(3x - 4) = 0
x = 4/3
Substituting x = 4/3
into f(x)
3x^3 - 6x^2 - 9
3(4/3)^3 - 6(4/3)^2 - 9
- 12.55
Turning point (4/3, -12.55)
Hope this helps:-)