Question 980149
x^5-11x^4+13x^3-143x^2= 36x-396

x^4(x-11) + 13x^2(x-11) =36 (x-11)
(x^4+13x^2-36) (x-11)=0
x=11, 1 root

(1/2)(-13 +/- sqrt (169+144)) ;; sqrt 313=17.69
(1/2) (-13+/-17.69)
x^2=-30.69
x=+/- i sqrt(30.69)

x^2=2.345
x=+/- 1.531

There are 3 real roots, 11 and a conjugate pair of irrational roots.
There are two complex roots.
The graph goes from minus infinity through the negative irrational root, peaks at y=396 at x=0, and then descends through the positive rational root and then ascends again, crossing the x-axis at x=11 ascending to infinity.

{{{graph(300,300,-20,20,-10000,10000,x^5-11x^4+13x^3-143x^2-36x+396)}}}