Question 980087
A=Ao{1+r/n}^nt

{1+.08/2}^34+1200={1+.12/3}}^51

1.04^34+ 1200= {1/04}^51
3.7943 +1200=7.3909

In other words,
A for A=3.7943*Ao
A for B=7.3909*Ao
3.7943Ao+1400=7.3909Ao, since I need to add $1400 to A to match B.
1400=3.5967Ao
Ao=$389.25

389.25{1.04}^34=$1476.94
389.25(1.04)^51=2876.93, $1400 more within rounding error.

The answer is $389.25