Question 83593
Since the perimeter is 

{{{P=2L+2w}}}


we can factor out a 2 to make the equation


{{{P=2(L+w)}}}


Now plug in  {{{L=x/(2x-5)}}} and {{{w=8/(2x-5)}}}


{{{P=2(x/(2x-5)+8/(2x-5))}}}


Since we have a common denominator, we can add the fractions



{{{P=2((x+8)/(2x-5))}}} Combine the fractions



{{{P=(2x+16)/(2x-5)}}} Multiply


So the perimeter of a rectangle with a length of {{{x/(2x-5)}}} and a width of{{{8/(2x-5)}}} is {{{(2x+16)/(2x-5)}}}