Question 979684
Solve 2log6+log12-log16
The equiv of 2log(6)
{{{log(6^2)}}} = log(36)
therefore:
log36 + log12 - log16
:
we can write this:
{{{log(((36*12)/16))}}} = {{{log((432/16))}}} = log(27) = 1.431364