Question 979768


You are given an equation 


{{{2x - 5 = 3/x}}}.


First, &nbsp;multiply both sides by &nbsp;<B>x</B>. &nbsp;You will get


{{{2x^2 - 5x -3}}} = {{{0}}}.


Now factor the quadratic polynomial in the left side:


{{{2x^2 - 5x -3}}} = {{{2*(x-3)*(x+1/2)}}}.


(check it!) 


Hence, &nbsp;the roots are {{{x[1]}}} = {{{3}}} and {{{x[2]}}} = {{{-1/2}}}.