Question 83569
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find area of a ideal triangle 3x4x5

The formula for the area of a triangle is 

     {{{A}}} = {{{1/2}}}base×altitude

A 3-4-5 triangle is a right triangle because it
satisfies the Pythagorean theorem:

a˛ + b˛ = c˛
3˛ + 4˛ = 5˛
 9 + 16 = 25
     25 = 25

{{{drawing(200,200,-1,5, -1,5,

    locate(1,-.1,"b=3"), locate(3.1,2,"a=4"), 
    locate(.6,2,"c=5"), line(2.7,0,2.7,.3), line(2.7,.3,3,.3),

    triangle(0,0,3,0,3,4) )}}}  

So the base is b which is 3, and the altitude is a which is 4.

Substituting into the formula for the area:

        A = {{{1/2}}}×base×altitude
        A = {{{1/2}}}×3×4
        A = {{{1/2}}}×12
        A = 6 square units

Edwn</pre>