Question 978273
<pre>
Prime factorization is unique except for the order of factors.

n could only be 3 because

(q^3*p^2)/r^2 = s^n

then
q^3*p^2= r^2*s^n

There are 5 primes multiplied together on the left, so
there must the same 5 primes multiplied together on the right.

In fact p=r and q=s, and of course n=3.

Edwin</pre>