Question 979493
Initially, {{{t=0}}}
{{{T(0)=67+148e^0}}}
{{{T(0)=67+148}}}
{{{T(0)=215}}}
.
.
{{{T(10)=67+148e^(-0.5)}}}
{{{T(10)=67+89.8}}}
{{{T(10)=156.8}}}
.
.
{{{100=67+148e^(-0.05t)}}}
{{{148e^(-0.05t)=33}}}
{{{e^(-0.05t)=0.22297}}}
{{{-0.05t=ln(0.22297)}}}
{{{t=-20*ln(0.22297)}}}