Question 83549
Find the absolute inequality corresponding to x<=-22/3 or x>=11/3.

------------
Try a geometrical approach.
On a number line put -22/3 and +11/3
The midpoint between them is (-22/3+11/3)/2 = -11/3/2 = -11/6
----------------
The distance from -11/6 to 11/3 (or to -22/3) is 33/6
-------------------
You want to express all the x-values that are greater than or equal to 
33/6 from -11/6
---------------------
That would be |x-(-11/6)|>=33/6
or
|x+(11/6)|>=11/2
-------------
Cheers,
Stan H.