Question 979331
A rectangle has the width x and it's [sic] length is 10 greater hang he width. For what values of x the area of the rectangle is greater or equal to 24
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Area = x*(x+10)
Find x for Area = 24.
x*(x+10) = 24
{{{x^2 + 10x - 24 = 0}}}
(x+12)*(x-2) = 0
x = -12
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Ignore the negative solution.
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x = 2
x >=2 --> Area >=24
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