Question 979333
first integer is x
second is (x+1)
5x+(x+1)^2=121
5x+x^2+2x+1=121
5x+x^2+2x=120
x^2+7x-120=0
(x+15)(x-8)=0

x=-15, +8

Want only positive integers
8 and 9

square of second is 81
5 times the first is 40
They add to 121