Question 979306
I am a two digit odd number.The sum of my digits is 5.
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Two possibilities:  41 or 23
</pre>
I am the sum of five different odd numbers which are all greater than zero but
less than eleven.
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Only possibility: 1+3+5+7+9 = 25
</pre>
I am a three digit number less than 500 but greater than 200. All my digits are
odd. The sum of my digits is 5.
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It has to begin with the odd digit 3 to be between greater than 200 and less
than 500.  So the other two digits must have sum 2.  So they can only be two
1's.  Answer: 311
</pre>
I am a three digit number. My tens digit is 5 more than my ones digit.  My
hundreds digit is 8 less than my tens digit.
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The hundreds digit can't be 0, so the only way the hundreds digit could be 8
less than the tens digit is for the tens digit to be 9 and the hundreds digit to
be 1. Since the tens digit is 9 and it is 5 more than the ones digit, the ones
digit can only be 4.  Answer: 194

Edwin</pre>