Question 979285
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Let *[tex \Large T] represent the capacity of a full tank.  From the problem we have that


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{1}{4}T\ +\ G\ =\ \frac{7}{8}T]


Solve for *[tex \Large G]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ G\ =\ \frac{5}{8}T]


Now all you have to do is solve for *[tex \Large T]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \