Question 979209
Let x=the numerator and y= the denominator                                                                                                  Now we are told that
2x=y+2----------equation (1)
and (x+3)/(y+3)=2/3
        3(x+3)=2(y+3)
         3x+9=2y+6
         3x-2y=-3------------equation (2)
     Solve from eqn. (1) and (2) we get, 
        2x-y=2----------(1)×2
        3x-2y=-3--------(2)×1
 Now eqn.(1)-(2) we get, 
  4x-2y=4 
  3x-2y=-3
                                               X=7
   And from equation(1)     y=12 
   Therefore, original fraction x/y=7/12.