Question 979140
Three people put their money together to buy lottery tickets.
 The first person put in $15, the second person put in $32, and the third person put in $43.
 One of the tickets was a winning ticket.
 If the winning ticket paid $4.5 million, what was the first person's share of the winnings? 
:
Add up the 3 amts to find the total cost of the ticket
15 + 32 + 43 = 90 
then the fractions for each will be
{{{15/90}}}, {{{32/90}}}, and {{{43/90}}}
find the 1st person's winnings
{{{15/90}}} can be reduced to {{{1/6}}}, therefore
{{{1/6}}} * 4,500,000 = $750,000