Question 979136
 John can finish a work in 8days and peter can finish that same work in 6days.
They worked together for 2days and peter left.
How long will it take John to finish the work himself?
:
let t = time for John to finish the job
let the completed job = 1
:
Peter works 2 days
John works (t+2) days
:
A shared work equation, each does a fraction of the job, the two fractions add up to 1
{{{((t+2))/8}}} + {{{2/6}}} = 1
multiply equation by least common multiple, 24; cancel the denominators
3(t+2) + 4(2) = 24
3t + 6 + 8 = 24
3t = 24 - 14
t = 10/3
t = 3.33  additional hrs for John to finish the job (3 hrs 20 min)
:
:
Check this (John work a total of 5.33 hrs)
{{{5.33/8}} + {{{2/6}}} =
.667 + 333 = 1.0