Question 979108
When they are {{{ 60 }}} mi apart, Just imagine
that one of them, say Morgan, stops and the
other, Andy, starts heading toward Morgan at
the sum of their speeds.
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Let Morgan's speed = {{{ s }}} mi/hr
The sum of their speeds is: {{{ 55 + s }}} mi/hr
They pass eachother in {{{ 1/2 }}} hr
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Now I can say:
{{{ 60 = ( 55 + s )*(1/2) }}}
{{{ 120 = 55 + s }}}
{{{ s = 65 }}}
Morgan is driving 65 mi/hr
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check:
Andy's equation:
{{{ d[1] = 55*(1/2) }}}
{{{ d[1] = 27.5 }}} mi
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Morgan's euation:
{{{ d[2] = 65*(1/2) }}}
{{{ d[2] = 32.5 }}} mi
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{{{ d[1] + d[2] = 27.5 + 32.5 }}}
{{{ d[1] + d[2] = 60 }}} mi
OK