Question 979083
{{{m[1]=(k*sqrt(y))/(p^2*n)}}}
{{{m[2]=(k*sqrt(4y))/((3p)^2*(2n))}}}
{{{m[2]=(2k*sqrt(y))/(18p^2*n)}}}
{{{m[2]=(1/9)((k*sqrt(y))/(p^2*n))}}}
{{{m[2]=(1/9)m[1]}}}
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You were almost there but you didn't square the 3 when you tripled p,
That would give you
{{{2/(9*2)=1/9}}}