Question 978999

The question is solve the inequality for Algebra II
 3x-4/x+3<2 what is the solution? May I have step by step. Thank you so much
<pre>{{{(3x - 4)/(x + 3) < 2}}}, with {{{x <> - 3}}}, so one of the critical values is at: {{{- 3}}}
3x - 4 < 2(x + 3) ------- Multiplying by LCD, x + 3
3x - 4 < 2x + 6
3x - 2x < 6 + 4
x < 10

This now gives us the 2 critical values: - 3 and 10, and the 3 intervals: 
1) x < - 3
2) - 3 < x < 10, and
3) x > 10
 
You'll now need to determine which intervals contain values that satisfy the original inequality. Doing this results in the solution: {{{highlight_green(- 3 < x < 10)}}}