Question 978950
If sandy is nine times older than Eric and in 10 years the sum of their ages will be 50, how old is Eric now?
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9 times older = 10 times as old.
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S = 10E
S+10 + (E+10) = 50
10E+10 + E+10 = 50
11E = 30
Eric is 30/11 years
Sandy is 300/11 years
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It's not an integer solution because 9 times older is not 9 times as old.
1 time older is not the same age, it's 2x as old.
etc.
9 times older --> a 900% increase in age --> 10 times as old.
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People who write math problems should know what they're talking about.
If they don't, they should remain in politics.