Question 978913
The volume of the liquid in the conical funnel is:

 {{{V=(1/3)(12pi)(15/2)^2=4pi*(225/4)}}}= {{{225pi cm^3}}}

The volume of this liquid in the cylindrical tin is the same:

{{{V=5^2pi*H}}} where H is the height of liquid in the cylinder.

Substituting in the last formula {{{V=225pi}}} the height will be:

{{{H=225pi/25pi= 9cm^3}}}