Question 978880
Ordinarily you want to work within grouping symbols first, but what is the computation like if you treat this as two binomials as a product?


{{{1^2-(1/2)*1-1*(1/3)+(1/2)(1/3)}}}


{{{1-1/2-1/3+1/6}}}


{{{1-3/6-2/6+1/6}}}


{{{1+1/6-5/6}}}


{{{1-2/3}}}


{{{highlight(1/3)}}}


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Working inside parentheses first,
{{{(1/2)(2/3)}}}
See  {{{(1/3)(2/2)}}}
{{{1/3}}}