Question 978775
The points I would use would be
let x=0; 3y=12, y=4  (0,4)
let y=0; 2x=12, x=6  (6,0)
pick x=3, since it is easier to use.
6+3y=12
3y=6
y=2 
(3,2)
Any time you have an equation like this where the coefficients are evenly divisible into the right side, set each term =0.

{{{graph(300,200,-10,10,-10,10,(-2x/3)+4)}}}