Question 978758
{{{4x^2-8x+3=0}}}
{{{4(x^2-2x)+3=0}}}
{{{4(x^2-2x+1)+3-4(1)=0}}}
{{{4(x-1)^2-1=0}}}
{{{4(x-1)^2=1}}}
{{{(x-1)^2=1/4}}}
{{{x-1=0 +- 1/2}}}
{{{x=1 +- 1/2}}}
{{{A=3/2}}}, {{{B=1/2}}}
So then,
{{{A+1/B=3/2+2=7/2}}}
and
{{{B+1/A=1/2+2/3=3/6+4/6=7/6}}}
and
{{{f(x)=(x-5/2)(x-7/6)}}}
{{{f(x)=a(2x-7)(6x-7)}}}
{{{f(x)=a(12x^2-56x+49)}}}
where {{{a}}} is any non-zero constant