Question 83295
solve for m
{{{S=H/(mt[1]-mt[2])}}}
{{{S(mt[1]-mt[2])=H(mt[1]-mt[2])/(mt[1]-mt[2])}}}
{{{S(mt[1]-mt[2])=H*cross((mt[1]-mt[2]))/cross((mt[1]-mt[2]))}}}
{{{Sm(t[1]-t[2])=H}}}
{{{Sm(t[1]-t[2])/(S(t[1]-t[2]))=H/(S(t[1]-t[2]))}}}
{{{cross(S)m*cross((t[1]-t[2]))/cross((S(t[1]-t[2])))=H/(S(t[1]-t[2]))}}}
{{{m=H/(S(t[1]-t[2]))}}}  Some teachers want this.
{{{m=H/(St[1]-St[2])}}}  Others want this.
Happy Calculating!!!!