Question 978531
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_b(b)\ =\ 1\ \forall\ b\ >\ 0\ \in\ \mathbb{R}]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \log_9(9)\ -\ 1\ =\ 1\ -\ 1\ =\ 0]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \