Question 978532
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The zeros of the function are all zeros of the numerator polynomial that are not equal to a zero of the denominator.  The discontinuity is the zero of the denominator polynomial.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \