Question 978484
<pre>
You forgot to tell us how much the tickets cost each.
So I just arbitrarily chose that the price of a student 
ticket is $4 and the price of a non-student ticket is $6. 
<pre>

Let the number of student tickets be x
Let the number of non-student tickets be y

                      Price     Money
 Type      Number      of        from
  of        of        EACH       ALL
ticket    tickets     ticket   tickets
-------------------------------------------
student      x         $4       $4x
non-student  y         $6       $6y
-------------------------------------------
TOTALS      48       -----     $220

 The first equation comes from the second column.

  {{{(matrix(4,1,Number,of,student,tickets))}}}{{{""+""}}}{{{(matrix(4,1,Number,of,non-students, tickets))}}}{{{""=""}}}{{{(matrix(4,1,total,number,of,tickets))}}}
               x + y = 48

The second equation comes from the last column:

  {{{(matrix(5,1,Money,from,ALL,student,tickets))}}}{{{""+""}}}{{{(matrix(5,1,Money,from,ALL,non-student,tickets))}}}{{{""=""}}}{{{(matrix(5,1,Total,money,from,ALL,tickets))}}}

             4x + 6y = 220

So we have this system of equations:

{{{system(x + y = 48,4x + 6y = 220)}}}.

We solve by substitution.  Solve the first equation for y:

               x + y = 48
                   y = 48 - x

Substitute (48 - x) for y in 4x + 6y = 220

   4x + 6(48 - x) = 220
    4x + 288 - 6x = 220
        -2x + 288 = 220
              -2x = -68
                x = 34 = the number of student tickets.

Substitute in y = 48 - x
              y = 48 - (34)
              y = 14 non-student tickets.

Checking:  34 student tickets brings in $136 and 14 non-students is $84
            That's 48 tickets.
            And indeed $136 + $84 = $220

Edwin</pre>