Question 978463
 
{{{y = 9 - x^2}}}...to find the inverse, swap {{{x}}} and {{{y}}}

{{{x = 9 -y^2}}}.....solve for {{{y}}}

{{{y^2 = 9 -x}}}

{{{y = sqrt(9 -x)}}}=>the inverse

so, the inverse of the function {{{y = 9 -x^2}}}, for all values {{{x >= 3}}}
is {{{y = sqrt(9 -x)}}}, where {{{x}}} can take values {{{x<=9}}}
(assuming a function from reals to reals)


{{{drawing( 600, 600, -10, 10, -10, 10,
locate(2,4,f(y=9 - x^2)),locate(4,-2,inverse(y=sqrt(9 -x))),
 graph( 600, 600, -10, 10, -10, 10, 9 - x^2,sqrt(9 -x),-sqrt(9 -x))) }}}