Question 978348


the {{{x-intercept}}} is the value of {{{x}}} for which {{{y=0}}}:({{{x}}},{{{0}}})

so, to find the {{{x-intercept}}} for the equation {{{y=-(1/2)x+3}}}, set {{{y=0}}} and solve for {{{x}}}

{{{0=-(1/2)x+3}}}

{{{(1/2)x=3}}}

{{{cross(2)(1/cross(2))x=3*2}}}

{{{x=6}}}

the {{{x-intercept}}} is at ({{{6}}},{{{0}}})


{{{ graph( 600, 600, -10, 10, -10, 10, -(1/2)x+3) }}}