Question 978309
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5000\ =\ 3200(1\ +\ i)^6]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \ln(1\ +\ i)\ =\ \frac{\ln\left(\frac{5000}{3200}\right)}{6}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ i\ =\ e^{\left(\frac{\ln\left(\frac{5000}{3200}\right)}{6}\right)}\ -\ 1]


Just do the arithmetic.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it

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*[tex \LARGE \ \ \ \ \ \ \ \ \ \