Question 978314
The length of a rectangle is twice its width. 
Let width be "x"::
Then length is "2x"::
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If its length is decreased by 3m and its width is increased by 2m, the area of the resulting rectangle is 30m^2. Find the dimension.
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New length::  2x-3
New width:: x+2
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Equation::
(2x-3)(x+2) = 30
2x^2 + x - 6 = 30
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2x^2 + x - 36 = 0
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(x-4)(2x+9) = 0
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Positive solution::
x = 4m (original width)
2x = 8m (original length)
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Cheers,
Stan H.
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